(6z²+z-1)(9z-5) polynomial equation

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Sophiesunshinex Sophiesunshinex

01-05-2016
Mathematics

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(6z²+z-1)(9z-5) polynomial equation

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how do you write 4540 million in standard form?

BossLife123 BossLife123 · Answer 1 · 2016-05-01T22:12:58+02:00

BossLife123 BossLife123

01-05-2016

Hi there, (6z²+z-1)(9z-5)=(6z²+z+-1)(9z+-5)=(6z²)(9z)+(6z²)(-5)+(z)(9z)+(z)(-5)+(-1)(9z)+(-1)(-5)=54z³-30z²+9z²-5z-9z+5=54z³-21z²-14z+5. Therefore, the answer is 54z³-21z²-14z+5.

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