Dimajago
Dimajago Dimajago
  • 03-07-2020
  • Mathematics
contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

EpicMinion900 EpicMinion900
  • 03-07-2020

Answer:

21

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

Answer Link

Otras preguntas

SCHOOL START TOMORROW HELPPP PLEASEEE. JUST NUMBER 3
Please answer!!!! School is coming up soon!!! If you answer I will put you as “ the brainiest answer” !!!!
Use dimensional analysis to convert the width of a bedroom to feet if it measures 132 inches.
6. The points below represent a direct variation, findthe missing value between the points.(6,10) and (24,y)​
Which one is better EBAY or AMAZON + why? BRAINLIEST WILL BE GIVEN
Which of the following could have the electron configuration 2.8? I. Sodium (Na) atom II. Lithium (Li) ion III. Oxygen (O) ion IV. Neon (Ne) atom V. Sulfur
Which of the following is an accurate description of a Type I: Offshore Life Jacket (PFD)? It is designed for calm, inland waters It is designed for open, rou
Find the distance between the pair of parallel lines. y = 2x + 4 y = 2x – 4 A) 4.01 B) 3.84 C) 3.58 D) 3.65
HELPPPPPPP!!!!!!!!!!!!!!!! A ball is thrown from an initial height of 2 meters with an initial upward velocity of 11 m/s. The ball's height h (in meters) after
why is Sikim not in the seven sisters ​​