Respuesta :

given expression,

[tex](w^0\ast x^{-3})^{-2}[/tex]

let us simplify,

[tex]\begin{gathered} (w^0\ast x^{-3})^{-2} \\ =\frac{1}{(w^0\ast x^{-3})^2} \\ =\frac{1}{w^0}\ast\frac{1}{(x^{-3})^2} \\ =1\ast\frac{1}{x^{-6}} \\ =\frac{1}{\frac{1}{x^6}} \\ =x^6 \end{gathered}[/tex]

the base is x.

the exponent is 6.

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