Find the center and radius for the circle, given the equation: x^2-14x+y^2+8=16

Question

03-07-2017
Mathematics

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Find the center and radius for the circle, given the equation: x^2-14x+y^2+8=16

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Аноним Аноним · Answer 1 · 2017-07-03T15:18:54+02:00

Аноним Аноним

03-07-2017

you can do this by completing the square

x^2 - 14x + y^2 + 8 = 16

(x - 7)^2 - 49 + (y + 4)^2 - 16 = 16

(x - 7)^2 + (y + 4)^2 = 16 + 16 + 49 = 81

so the center is at (7 , -4) and radius = sqrt81 = 9

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