Respuesta :

BenjaminG123
Greetings!

"Solve for b"...

[tex]3b-4/2 = c[/tex]
[tex]3b-2= c[/tex]\
Add 2 to both sides.
[tex](3b-2)+2=(c)+2[/tex]
Simplify.
[tex]3b=c+2[/tex]
Divide both sides by 3.
[tex](3b)/3=(c+2)/3[/tex]
Simplify.
[tex]b=1/3c+2/3[/tex]

The answer would be: b=1/3c+2/3

Hope this helps.
-Benjamin

Answer:  The required solution for b is [tex]b=\dfrac{2c+4}{3}.[/tex]

Step-by-step explanation:  We are given to solve the following equation for b :

[tex]\dfrac{3b-4}{2}=c~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

To solve the given equation for b, we must take b on one side of the equation and all other terms on the other side.

From equation (i), we get

[tex]\dfrac{3b-4}{2}=c\\\\\Rightarrow 3b-4=2c\\\\\Rightarrow 3b=2c+4\\\\\Rightarrow b=\dfrac{2c+4}{3}.[/tex]

Thus, the required solution for b is [tex]b=\dfrac{2c+4}{3}.[/tex]