if an aqueous solution containing M2+ ions electrolyzed by a current of 3.00 A for 60.0 min., resulting in 3.66 g of solid M produced at a cathode during this time, what is the likely identity of the element M
W = I t e / F Where, W = Amount deposited = 3.66 g I = Current = 3 A t = Time = 60 min = 3600 s e = Chemical equivalence F = Faraday's Constant = 96500 Solving for e, e = F W / I t Putting Values, e = (96500×3.66) ÷ (3 × 3600) e = 32.7 As we know, e = M / 2 solving for M, M = e × 2 Putting value of e, M = 32.7 × 2